2=-8t^2+1.6t+4

Solution for 2=-8t^2+1.6t+4 equation:

2=-8t^2+1.6t+4

We move all terms to the left:

2-(-8t^2+1.6t+4)=0

We get rid of parentheses

8t^2-1.6t-4+2=0

We add all the numbers together, and all the variables

8t^2-1.6t-2=0

a = 8; b = -1.6; c = -2;
Δ = b2-4ac
Δ = -1.62-4·8·(-2)
Δ = 66.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{66.56}}{2*8}=\frac{1.6-\sqrt{66.56}}{16}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{66.56}}{2*8}=\frac{1.6+\sqrt{66.56}}{16}
$